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Become familiar with types of errors and strategies for fixing them
Practice fixing the following code segments!
Intended behavior: create a list of characters from the string contained in the variable alphabet
%%js
var alphabet = "abcdefghijklmnopqrstuvwxyz";
var alphabetList = [];
for (var i = 0; i < 10; i++) {
alphabetList.push(alphabet[i]);
}
console.log(alphabetList)
<IPython.core.display.Javascript object>
I changed it so now there is one array, and it pushes alphabets index rather than the index as a number
Intended behavior: print the number of a given alphabet letter within the alphabet. For example:
"_" is letter number _ in the alphabet
Where the underscores (_) are replaced with the letter and the position of that letter within the alphabet (e.g. a=1, b=2, etc.)
%%js
var alphabet = "abcdefghijklmnopqrstuvwxyz";
var alphabetList = [];
for (var i = 0; i < 10; i++) {
alphabetList.push(alphabet[i]);
}
console.log(alphabetList)
let letterNumber = 5
for (var i = 0; i < alphabetList.length; i++) {
if (i === letterNumber) {
console.log(alphabetList[i-1] + ` is letter number ${i} in the alphabet`)
}
}
I changed the for loop now to iterate through the alphabet array’s length and to reference the letters index value rather than the index itself and used a ${} to embed the index without having to use a + operator
Intended behavior: print a list of all the odd numbers below 10
%%js
let evens = [];
let i = 1;
while (i <= 10) {
evens.push(i);
i+=2
}
console.log(evens);
I changed the script to start at 1 instead of 0.
The intended outcome is printing a number between 1 and 100 once, if it is a multiple of 2 or 5
%%js
var numbers = []
var i = 0
while (i < 101) {
if(i % 5 === 0 | i % 2 === 0)
{
numbers.push(i)
}
i += 1
}
console.log(numbers)
I changed the code to now work without a for loop, the while loop to iterate until 101, and combined the if statments into one
This code segment is at a very early stage of implementation.
Hint:
Then repeat this process until you get program working like you want it to work.
%%js
var menu = {"burger": 3.99,
"fries": 1.99,
"drink": 0.99}
var total = 0
//shows the user the menu and prompts them to select an item
console.log("Menu")
for (var item in menu) {
console.log(item + " $" + menu[item].toFixed(2)) //toFixed makes it only have 2 decimal places
}
//ideally the code should support mutliple items
var order = ["burger","drink","fries"]
//code should add the price of the menu items selected by the user
for(let i=0;i<order.length;i++)
{
let price = menu[order[i]]
let decimalPlace = (price + "").split(".")[1];
if(parseInt(decimalPlace) == 99) //4.99 = 5
{
price = Math.round(price)
}
total += price
}
console.log(total.toFixed(2))
//
I explained that to fixed is for decimal places, I then made order an array to support multiple choices Then finally I added an additional line to round any prices that were ending in .99 to the next dollar